c# - What "where" clause will make this Generic Method work? -

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consider admittedly contrived generic definition:

    private void foo<t,basetype>(propertyinfo prop, basetype o1, basetype o2)     {         t value1 = (t) prop.getvalue(o1, null);         t value2 = (t) prop.getvalue(o2, null);         if (value1 != value2)             console.writeline("not equal");     }

prop guaranteed propertyinfo basetype.

i getting compile error @ if() statement:

operator '!=' cannot applied operands of type 't' , 't'

while in "general case" understand error message valid, in case, want routine of standard types: system.int64, system.string, etc of support == , != operator.

i assume can fixed "where" clause, icomparable , iequalable don't help.

do know correct "where" clause is?

frank

since system.int64, system.string, etc .. list implement icomparable, use 

where t : icomparable

and use compareto() instead of !=

for eg. code compile

private void foo<t>(object o) t : icomparable {     t v1 = default(t);     t v2 = default(t);     if(v1.compareto(v2)  != 0)     {         console.writeline("not equal");     } }  private void bar() {     foo<string>(new object()); }

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