perl5 - Perl - pass code block as parameter inside parentheses -

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is possible pass block of code sub using "parentheses" syntax?

i.e. when write

list::moreutils::any { defined ($_) } (undef, undef, 1);

it works. when try add parentheses

list::moreutils::any ( { defined ($_) } , (undef, undef, 1) );

this interpreted anonymous hash, giving error message. neither escaping nor using eval helps.

the idea behind fuss if call part of expression, i.e.

if (first_index { defined (${$_})} $jms_positions > $jms_positionals_seen )

some operator following arguments might executed before call, producing undesired result.

an anonymous subroutine declared syntax 

sub { "the sub no name!" };

perl's prototype system allows special exception code block first parameter, in case can leave off leading sub , pass block, similar perl builtin. works when calling in parentheses-less style. using parens causes parser think want pass hash-ref.

so can 

list::moreutils::any( sub { defined }, undef, undef, 1 );

if insist on using parens.


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