html - Is this the correct way to check in PHP that a checkbox is checked? -

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i have code check tos checkbox checked: 

if (!isset($_post['tosagree'])) {//if user did not agree tos     $errors[] = '<span>please agree terms of service.<span>'; }

for reason allowing me register code there. weird thing if other field not field , field not checked print error, if problem allows user register.

update: seems problem weird in code. if feel looking through 217 lines of code here code: http://pastebin.com/ykerypef

whether !isset($_post['tosagree']) enough depends on browser.

to safe, set value attribute of checkbox. then, check if value present:

<input type='checkbox' value='agreed'/>

then this:

if (!isset($_post['tosagree']) || $_post['tosagree'] != "agreed" ) {     $errors[] = '<span>please agree terms of service.<span>'; }

also, when value attribute not explicitly specified, browsers set value on when checked.

edit

ok, know what's happening. in php code, have block:

if (!isset($_post['tosagree']) || $_post['tosagree'] != "agreed") {//if user did not agree tos     $errors[] = '<span>please agree terms of service.<span>'; }

then later have line:

if ($un && $e && $p && $ic) { //if there no errors

the problem don't have flag when tos checkbox isn't checked. error can't printed because in if statement have call exit().


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